bear: 试一下吧 [阅读: 351] 2007-06-19 07:33:52 select user_id, (case user_dataName when 'X' then USER_DATAVALUE end) as x,(case user_dataName when 'y' then USER_DATAVALUE end) as y,(case user_dataName when 'z' then USER_DATAVALUE end) as z from tableName